## CSci 2101 Problem set 5.

### Due Friday April 25th at 11:59pm

You may work individually or in pairs.

#### Problem 1 (8 points): Written part.

For this problem assume that given trees are binary (i.e. each node has at most two children, left and right), but not necessarily binary search trees, i.e. there is not relation between values of a parent and a child node. There is enough information given in each item to uniquely determine all nodes in the tree corresponding to that item.

1. Draw a picture of a tree that has the inorder traversal 5, 12, 10, 7, 8, 6, 3, 15 and the preorder traversal 7, 10, 5, 12, 3, 6, 8, 15.
2. Draw a picture of a tree that has the inorder traversal 9, 18, 2, 11, 6, 3, 7 and the postorder traversal 9, 11, 2, 18, 3, 7, 6.
3. Draw a picture of a binary search tree with the preorder traversal 10, 6, 3, 2, 8, 20, 15, 17.

#### Problem 2 (10 points): binary tree `equals` method

Add an `equals` method to the BinarySearchTree class. According to Java specification, equals method takes any object. It then checks if the parameter object is of the same type as this object (see `instanceof` check below). If the object passes the instanceof check, it is then typecast to BinarySearchTree<K,V>. See more on instanceof here: http://www.java2s.com/Tutorial/Java/0060__Operators/TheinstanceofKeyword.htm.

The method is declared and starts as follows:

``````
public boolean equals(Object obj) {
//  checking that obj is an OurLinkedList
if (!(obj instanceof  BinarySearchTree) ) return false;

// typecasting obj to BinarySearchTree
BinarySearchTree<K,V> otherTree = (BinarySearchTree<K,V>) obj;

// the rest of your code goes here, use otherTree variable:

}
``````

Two binary search trees are considered equal if all nodes of one tree correspond to nodes with equal keys, values, and position in the tree, and vice versa. Use `equals` method on values and on keys to check that they are equal.

Note that it is also the case that two trees are equal if and only if one has exactly the same in-order and post-order traversal as the other, but you are not allowed to use this property as a way to establish tree equality.

Test your method extensively using JUnit, submit all your test cases.

Submit the java file(s) with your testing code by e-mail to me. Make sure to CC your group partner (if any).

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